End-Devouring Rays

Low ★ Graph Theory » Infinite Graphs accessible to undergrads

Status solved high confidence

Gollin and Heuer (2017/2018) proved that every end $\omega$ of a graph either contains uncountably many disjoint rays or admits a set of disjoint $\omega$-rays that devours $\omega$ and starts at any prescribed feasible set of starting vertices. Their theorem explicitly confirms Georgakopoulos's conjecture, settling the case of countable ends with an arbitrary (in particular, infinite) set $K$ of pairwise disjoint $\omega$-rays.

Cited literature (1)

Reviewer notes. The arXiv abstract page (1704.06577) explicitly states the result confirms Georgakopoulos's conjecture. The journal version appeared in Discrete Mathematics 341 (2018), pp. 2117-2120, DOI 10.1016/j.disc.2018.04.012.

Auto-reviewed 2026-05-08 with claude-sonnet (subagent) (web search enabled).

Problem. Let $ G $ be a graph, $ \omega $ a countable end of $ G $ , and $ K $ an infinite set of pairwise disjoint $ \omega $ -rays in $ G $ . Prove that there is a set $ K' $ of pairwise disjoint $ \omega $ -rays that devours $ \omega $ such that the set of starting vertices of rays in $ K' $ equals the set of starting vertices of rays in $ K $ .
Keywords: end · ray

Discussion

We say that a set of rays $ K $ devours the end $ \omega $ if every ray in $ \omega $ meets some ray in $ K $ . An end is countable if there is a countable set of rays devouring it. If $ K $ is a finite set of rays then it is not hard to prove (see [G]) that this problem has a positive answer: Theorem For every graph $ G $ and every countable end $ \omega $ of $ G $ , if $ G $ has a set $ K $ of $ k\in \mathcal N $ pairwise disjoint $ \omega $ -rays, then it also has a set $ K' $ of $ k $ pairwise disjoint $ \omega $ -rays that devours $ \omega $ . Moreover, $ K' $ can be chosen so that its rays have the same starting vertices as the rays in~ $ K $ .

Bibliography

  • [G] A. Georgakopoulos, Infinite Hamilton Cycles in Squares of Locally Finite Graphs, Preprint.